After losing several key defensive players, the Rams are now adding to their core. NFL.com’s Tom Pelissero reports (via Twitter) that the team is signing defensive tackle A’Shawn Robinson. It’s a two-year deal worth $17MM.
The 2016 second-rounder had spent his entire career with the Lions. After starting all 16 games during the 2017 season, Robinson was limited to only 26 games (16 starts) over the past two years. Still, he combined for 89 tackles, 2.5 sacks, and two forced fumbles.
The Rams defense will look a whole lot different in 2020. Safety Eric Weddle retired, Cory Littleton, Michael Brockers, and Dante Fowler have all departed in free agency, and the team declined their option on usual slot corner Nickell Robey-Coleman. So far, the organization has added former first-rounder Leonard Floyd and re-signed Austin Blythe.
They’ve also replaced defensive coordinator Wade Phillips with Brandon Staley, so it’s safe to say that side of the ball is getting a complete makeover after Sean McVay’s dissatisfaction with the previous structure became evident.
Wow coming from a lions fan seems like a lot for A’Shawn
Yea seems like an over pay, but most free agent signings have been. Maybe he’ll be better in a 4/3 defense.
Rams are going to flop in the new stadium. They mortgaged their future to make a buzz coming to LA, but it hasn’t panned out. Probably the third best team in their division to start the season, and the Cardinals have more to be excited about too
They didn’t mortgage their future and they played in the super bowl so it did pan out to a certain extent.
Rams also wasted the 2019 Draft Day. They kept trading down for more pucks and they ended up outsmarting themselves.